Question

How do you solve `log 6x-3=-4`?

Answer 1

See explanation.

Explanation:

`log6x-3=-4`

First step is yo move all numbers (here `-3`) to right side:

`log6x=-4+3`

`log6x=-1`

Now we have to change the number into a logarithm using the formula: `b=log_a a^b`

`log6x=log0.1`

Now we can change the `log` equation to the equation using only expressions under `log` sign:

`6x=0.1`

`x=1/10-:6`

`x=1/10*1/6`

Answer:

`x=1/60`