What is the area of the rectangle with sides $6 x^{8}$ $6x^8$ and $5 x^{2}$ $5x^2$ ?

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What is the area of the rectangle with sides $6 x^{8}$ $6x^8$ and $5 x^{2}$ $5x^2$ ?

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Answer 1 · 2018-05-01T08:41:00

$30 x^{10} s q . u n i t s$ $30x^10 sq.units$

Explanation:

Area of a Rectangle = length times breadth
$\Rightarrow A r e a = 6 x^{8} \times 5 x^{2}$ $implies Area = 6x^8 xx 5x^2$
$= 6 \times 5 x^{8 + 2} = 30 x^{10}$ $= 6xx5x^(8+2) = 30x^10$

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What is the area of the rectangle with sides $6 x^{8}$ $6x^8$ and $5 x^{2}$ $5x^2$ ?

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