How do you solve #x + y = 4 and x – y = 6#? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer achyut · Stefan V. May 1, 2018 #x=5 and y = -1# Explanation: We have, #x+y=4# or # x=4-y" "(1)# Now, we have #x-y=6# or #(4-y)-y=6" "#[from #(1)#] or #4-2y=6# # -2y=6-4# # -2y=2# y= -1# So #x+y=4# or #x-1=4# # x=4+1# #x=5# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 21966 views around the world You can reuse this answer Creative Commons License