How do you solve ${2.2}^{x - 5} = 9.32$ $2.2^(x-5)=9.32$ ?

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How do you solve ${2.2}^{x - 5} = 9.32$ $2.2^(x-5)=9.32$ ?

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Answer 1 · 2018-05-03T13:25:30

$x \approx 7.831$ $x~~7.831$

Explanation:

${2.2}^{x - 5} = 9.32 ∣ {log}_{2.2} ()$ $2.2^(x-5)=9.32 |log_2.2()$
$x - 5 = {log}_{2.2} (9.32) ∣ + 5$ $x-5=log_2.2(9.32)|+5$
$x = {log}_{2.2} (9.32) + 5 \approx 7.831$ $x=log_2.2(9.32)+5~~7.831$

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How do you solve ${2.2}^{x - 5} = 9.32$ $2.2^(x-5)=9.32$ ?

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