How do you factor 49b^2+70b+25?

Question

How do you factor 49b^2+70b+25?

2 Answers

Impact of this question

1672 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-03T14:24:57

$(7 b + 5) (7 b + 5)$ $(7b+5)(7b+5)$ or ${(7 b + 5)}^{2}$ $(7b+5)^2$

Explanation:

$49 b^{2} + 70 b + 25$ $49b^2+70b+25$
$49 = 7 \cdot 7$ $49=7*7$
$25 = 5 \cdot 5$ $25=5*5$
Therefore, this could be a perfect square trinomial. Testing this:
$(7 b + 5) (7 b + 5)$ $(7b+5)(7b+5)$ Using FOIL:
$= 49 b^{2} + 35 b + 35 b + 25$ $=49b^2+35b+35b+25$
$= 49 b^{2} + 70 b + 25 = 49 b^{2} + 70 b + 25$ $=49b^2+70b+25=49b^2+70b+25$ Therefore, the factorization is
$(7 b + 5) (7 b + 5)$ $(7b+5)(7b+5)$ or ${(7 b + 5)}^{2}$ $(7b+5)^2$

Answer 2 · 2018-05-03T14:28:28

${(7 b + 5)}^{2}$ $(7b+5)^2$

Explanation:

$49 b^{2} + 70 b + 25 is a perfect square$ $49b^2+70b+25" is a "color(blue)"perfect square"$

$∙ x {(a + b)}^{2} = a^{2} + 2 a b + b^{2}$ $•color(white)(x)(a+b)^2=a^2+2ab+b^2$

$49 b^{2} = {(7 b)}^{2} \Rightarrow a = 7 b$ $49b^2=(7b)^2rArra=7b$

$25 = {(5)}^{2} \Rightarrow b = 5$ $25=(5)^2rArrb=5$

$and 2 a b = 2 \times 7 b \times 5 = 70 b$ $"and "2ab=2xx7bxx5=70b$

$\Rightarrow 49 b^{2} + 70 b + 25 = {(7 b + 5)}^{2}$ $rArr49b^2+70b+25=(7b+5)^2$

Science

Math

Humanities

... and beyond

How do you factor 49b^2+70b+25?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question