Please solve q 6?

enter image source here

1 Answer
CW
May 5, 2018

angleQSR=150^@∠QSR=150∘

Explanation:

enter image source here
Gien AB=AC, => DeltaABC is isosceles, => angleABC=angleACB=(180-110)/2=35^@
given DeltaAPC is equilateral, => angleACP=60^@
given DeltaBRC is equilateral, => angleBCR=angleBRC=60^@,
consider DeltaBQC, angleBQC=180-35-95=50^@
given SQ bisects angleBQC, => angleSQC=50/2=25^@
similarly, given SR bisects angleBRC, => angleSRC=60/2=30^@
As QSRC is a quadrilateral,
=> angleQSR=360-angleSRC-angleC-angleSQC
=> angleQSR=360-30-155-25=150^@

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