Please solve q 6?

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1 Answer
May 5, 2018

angleQSR=150^@QSR=150

Explanation:

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Gien AB=AC, => DeltaABC is isosceles, => angleABC=angleACB=(180-110)/2=35^@
given DeltaAPC is equilateral, => angleACP=60^@
given DeltaBRC is equilateral, => angleBCR=angleBRC=60^@,
consider DeltaBQC, angleBQC=180-35-95=50^@
given SQ bisects angleBQC, => angleSQC=50/2=25^@
similarly, given SR bisects angleBRC, => angleSRC=60/2=30^@
As QSRC is a quadrilateral,
=> angleQSR=360-angleSRC-angleC-angleSQC
=> angleQSR=360-30-155-25=150^@