How do you solve $6 (x - 1) + 4 (3 x - 2) = 32$ $6( x - 1) + 4( 3x - 2) = 32$ ?

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Answer 1 · 2018-05-05T08:14:00

$x = 2 \frac{5}{9}$ $x=2 5/9$

First expand the equation to get

$6 (x - 1) + 4 (3 x - 2) = 32$ $6(x - 1) + 4(3x - 2 ) = 32$

$6 x - 6 + 12 x - 8 = 32$ $6x - 6 + 12x -8 = 32$

Collect the like terms together to obtain

$6 x + 12 x - 6 - 8 = 32$ $6x + 12x -6 -8 = 32$

you get

$18 x - 14 = 32$ $18x -14 = 32$

$18 x = 32 + 14$ $18x = 32 +14$

$18 x = 46$ $18x = 46$

$x = \frac{23}{9}$ $x = 23/9$

How do you solve 6(x−1)+4(3x−2)=326( x - 1) + 4( 3x - 2) = 32?