What is e(exponential) term in intigration?

1 Answer
May 5, 2018

#e# by itself is a constant. If it has an exponent with a variable, it is a function.

Explanation:

If you see it as something like #int_# #e^(2+3) dx# it will just be equal to #e^5x + C#. If you see it as #int_##e dx# it will be equal to #ex + C#.

However, if we have something like #int_# #e^x dx# it will follow the rule of #int_e^(k*x)dx = 1/k*e^(kx)+C#. Or in our case #int_e^(1*x) dx = 1/1e^(1*x)+C=e^x+C#.