Please solve q 7?

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1 Answer
May 6, 2018

BE=0BE=0

Explanation:

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Given AB=AC, ADAB=AC,AD // BCBC, and ADCADC is equilateral,
=> angleCAD=angleCDA=60^@CAD=CDA=60,
=> angleACB=60^@, => DeltaABC is also equilateral,
=> AB=BC=AC=AD=DC,
=> ABCD is a rhombus,
We know that the diagonals of a rhombus bisect opposite angles,
given that the bisector of angleD meets AB at E,
=> E coincides with B,
=> the angle bisector is the diagonal DB,
=> BE=0