Please solve q 20?

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1 Answer
CW
May 7, 2018

2011sqrt22011√2 cm

Explanation:

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Let angleBAC=x∠BAC=x
let AA be the area of DeltaABC
A=1/2*AB*AC*sinx
we know that sinx has a maximum value of 1 ,
when sinx=1, A has the maximum value.
=> x=90^@
and given AB=AC=2011 cm
angleABC=ACB=45^@
=> BCsin45=AB
=> BC*1/sqrt2=2011
=> BC=2011sqrt2 cm

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