How do you multiply $x^{0} y^{2} \cdot 3 y x^{5}$ $x^ { 0} y ^ { 2} \cdot 3y x ^ { 5}$ ?

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Answer 1 · 2018-05-07T11:42:22

$3 \cdot x^{5} \cdot y^{3}$ $3*x^5*y^3$

$x^{0} y^{2} \cdot 3 y x^{5} =$ $x^0y^2*3yx^5=$

$3 \cdot x^{0 + 5} \cdot y^{2 + 1} =$ $3*x^(0+5)*y^(2+1)=$

$3 \cdot x^{5} \cdot y^{3}$ $3*x^5*y^3$

Answer 2 · 2018-05-07T11:43:49

$= 3 y^{3} x^{5}$ $=3y^3x^5$

Using the power rule:

$a^{n} \cdot a^{m} = a^{n + m}$ $a^n*a^m=a^(n+m)$

$x^{0} \cdot x^{5} = x^{5}$ $x^0*x^5=x^5$

(where $x^{0}$ $x^0$ is also equivalent to $1$ $1$ )

$y^{2} \cdot 3 y = y^{2} \cdot 3 y^{1} = 3 y^{3}$ $y^2*3y=y^2*3y^1=3y^3$

Therefore, the solution to $x^{0} y^{2} \cdot 3 y x^{5}$ $x^0y^2*3yx^5$ is:

$= 3 y^{3} x^{5}$ $=3y^3x^5$

How do you multiply x0y2⋅3yx5x^ { 0} y ^ { 2} \cdot 3y x ^ { 5}?