How do you solve #5b - 5( 2- 5b ) = - 5( - 7b - 2)#?

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Answer 1 · 2018-05-09T11:27:18

By arranging

#5b - 5(2-5b) = -5(-7b-2)#

First get rid of parantheses:

#5b - 10 + 25b = 35b + 10#

Now collect terms (include b) on the left hand side and numbers on the other:

#30 b - 35 b = 10 + 10#

#-5b = 20#

#b=-20/5 = -4#

Your answer is #b=-4#