A rectangle has an area of 8z² - 12z. If its width is 4z, what is its length? What is the perimeter of the rectangle?

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Answer 1 · 2018-05-10T00:37:54

#l=2z-3#

#P=12z-6#

.

#A=8z^2-12z#

Area of a rectangle is:

#A=l*w# where #l# is the length and #w# is the width.

#8z^2-12z=l*w#

#w=4z#

#8z^2-12z=4z*l#

#4z(2z-3)=4z*l#

#l=(4z(2z-3))/(4z)=2z-3#

Perimeter of a rectangle is:

#P=2l+2w#

#P=2(2z-3)+2(4z)=4z-6+8z=12z-6#