Please solve q 96 ?

enter image source here

1 Answer
May 11, 2018

#BED=12^@#

Explanation:

enter image source here
In #BCE, angleBDC=180-78-24=78^@#
as #angleBDC=angleDBC=78^@, => color(red)(CD=CB)#
In #DeltaBCE, angleBEC=180-51-78=51^@#
as #angleBEC=angleEBC=51^@, => color(red)(CE=CB)#
#=> CB=CD=CE#
#=> B,D and E# are on a circle with center at #C#, as shown in the figure.
recall that the angle subtended at the center of a circle is twice the angle subtended at the edge from the same two points,
#=> angleBCD=2angleBED#,
#=> angleBED=(angleBCD)/2=24/2=12^@#