How do you evaluate $3\sqrt { 5} + 3\sqrt { 24} - \sqrt { 45}$ ?

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Answer 1 · 2018-05-11T17:01:22

Answer: $6sqrt6$

Here,

factors of 24 = 2.2.2.3 = $2^( 2).6$
factors of 45 = 3.3.5 = $3^(2).5$

Now,

= $3sqrt5+3.sqrt(2^(2).6)-sqrt(3^(2).5)$
= $3sqrt5+3.2sqrt6-3sqrt5$
= $6sqrt6$ [Since $3sqrt5$ is subtracted from $3sqrt5$ that results 0]

How do you evaluate 3\sqrt { 5} + 3\sqrt { 24} - \sqrt { 45}3\sqrt { 5} + 3\sqrt { 24} - \sqrt { 45}?