How do you simplify #(x^2+5x+6)/(x+1) * (x^2-1)/(x+3)#?

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Answer 1 · 2018-05-12T00:28:42

#x^2 + x - 3#

#(x^2 + 5x + 6)/ (x+1)# • #(x^2 - 1)/ (x+3) #

Factor out the numerators:

# ((x+3)(x+2))/(x+1)# • #((x+1)(x-1))/(x+3)#

Cross simplify to get:

#(x+2)/1# • #(x-1)/1#

Make it into factoring:

#(x+2)# • #(x-1)#

You get:

#x^2 + x - 3#