How do you simplify $(x^2+5x+6)/(x+1) * (x^2-1)/(x+3)$ ?

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Answer 1 · 2018-05-12T00:28:42

$x^2 + x - 3$

$(x^2 + 5x + 6)/ (x+1)$ • $(x^2 - 1)/ (x+3)$

Factor out the numerators:

$((x+3)(x+2))/(x+1)$ • $((x+1)(x-1))/(x+3)$

Cross simplify to get:

$(x+2)/1$ • $(x-1)/1$

Make it into factoring:

$(x+2)$ • $(x-1)$

You get:

$x^2 + x - 3$

How do you simplify (x^2+5x+6)/(x+1) * (x^2-1)/(x+3)(x^2+5x+6)/(x+1) * (x^2-1)/(x+3)?