Question

Please solve q 21?

Answer 1

`k=1/2`

Explanation:

As consecutive angles of a parallelogram are supplementary,
`=> angleP+angleQ=180^@`
`=> 3x+3y=180^@, => 3(x+y)=180^@, => x+y=60^@`
In `DeltaPNQ, anglePNQ=180-(x+y)=180-60=120^@`
In `DeltaPMQ, anglePMQ=180-2(x+y)=180-(2*60)=60^@`
given that `k*anglePNQ=anglePMQ`,
`=> k=(anglePMQ)/(anglePNQ)=60/120=1/2`