How do you find the perimeter of a triangle whose coordinates are (0,0) (6,8) ( 12,0)?

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Answer 1 · 2018-05-12T19:14:14

$P=32$

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$A(0,0),B (6,8),C (12,0)$

We use the distance formula to find the length of each side. Then we add them together. The distance formula is:

$d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)$

$AB=sqrt((6-0)^2+(8-0)^2)=sqrt(36+64)=sqrt100=10$

$BC=sqrt((12-6)^2+(0-8)^2)=sqrt(36+64)=sqrt100=10$

$AC=sqrt((12-0)^2+(0-0)^2)=sqrt(144+0)=sqrt144=12$

$P=AB+BC+AC=10+10+12=32$