How do you simplify $\frac{x^{2} + 7 x - 8}{x^{2} + 6 x - 7}$ $(x^2+7x-8)/(x^2+6x-7 )$ ?

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Answer 1 · 2018-05-13T04:00:50

$\frac{x - 8}{x - 7}$ $(x-8)/(x-7)$

1) Factorize the numerator and denominator:

$\frac{(x - 8) (x + 1)}{(x - 7) (x + 1)}$ $((x-8)(x+1))/((x-7)(x+1))$

2) Find the common factor and divide it, which in this case is (x+1)

$\frac{x - 8}{x - 7}$ $(x-8)/(x-7)$

3) Fraction simplified!!!

How do you simplify (x^2+7x-8)/(x^2+6x-7 )x2+7x−8x2+6x−7(x^2+7x-8)/(x^2+6x-7 )?