How do I express -3+4j and -3-4j in complex polar form, using radian measure?

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How do I express -3+4j and -3-4j in complex polar form, using radian measure?

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Answer 1 · 2018-05-13T15:36:38

For exact radfian measure you could put the value of $π, θ and α$ $pi, theta and alpha$

Explanation:

Multiply and divide by $5$ $5$ we get $5 (- \frac{3}{5} + \frac{4}{5} j)$ $5(-3/5+4/5j)$
In polar form we get $5 (cos α + sin α j)$ $5(cosalpha+sinalpha j)$
Where absolute $tan α = ∣ ∣ ∣ - \frac{4}{3} ∣ ∣ ∣ or α = π - {tan}^{- 1} (\frac{4}{3})$ $tanalpha=|-4/3|or alpha=pi-tan^-1(4/3)$ as $α$ $alpha$ lies in second quadrant

Similarly $- 3 - 4 j$ $-3-4j$ would be $5 (cos θ + sin θ j)$ $5(costheta+sintheta j)$ where
$tan θ = ∣ ∣ ∣ \frac{4}{3} ∣ ∣ ∣ or θ = {tan}^{- 1} (\frac{4}{3}) - π$ $tantheta=|4/3| or theta= tan^-1(4/3)-pi$ as $θ$ $theta$ lies in 3rd quandrant.

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How do I express -3+4j and -3-4j in complex polar form, using radian measure?

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Explanation:

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