How do you simplify $\frac{- 35 u^{3} v^{2}}{49 u^{3} v^{5}}$ $\frac { - 35u ^ { 3} v ^ { 2} } { 49u ^ { 3} v ^ { 5} }$ ?

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How do you simplify $\frac{- 35 u^{3} v^{2}}{49 u^{3} v^{5}}$ $\frac { - 35u ^ { 3} v ^ { 2} } { 49u ^ { 3} v ^ { 5} }$ ?

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Answer 1 · 2018-05-14T07:26:32

see below

Explanation:

We have, $\frac{- 35 u^{3} v^{2}}{49 u^{3} v^{5}}$ $frac{-35u^3v^2}(49u^3v^5)$
On further simplification, we get,
$\frac{- 5}{7 v^{3}}$ $frac{-5}(7v^3)$
Thus,the expression becomes $\frac{- 5}{7 v^{3}}$ $frac{-5}(7v^3)$

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How do you simplify $\frac{- 35 u^{3} v^{2}}{49 u^{3} v^{5}}$ $\frac { - 35u ^ { 3} v ^ { 2} } { 49u ^ { 3} v ^ { 5} }$ ?

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How do you simplify $\frac{- 35 u^{3} v^{2}}{49 u^{3} v^{5}}$ $\frac { - 35u ^ { 3} v ^ { 2} } { 49u ^ { 3} v ^ { 5} }$ ?