Question

How do you simplify `(x^2+3x+2)/(x^2-1)`?

Answer 1

`(x²+3x+2)/(x²-1)=(x+2)/(x-1)`

Explanation:

`(x²+3x+2)/(x²-1)`
`=(cancel((x+1)) (x+2))/((x-1)cancel((x+1)))`
`=(x+2)/(x-1)`
\0/ here's our answer!

Answer 2

First we should split the middle term

By the video... you should have understood that we need to make `3x` in two number that one is divisible by 2 and the other is divisible itself

`(x^2+x+2x+2)/(x^2-1)`

You should always remember that
`1=1^2`
It'll always help you

Factorize
`(x(x+1)+2(x+1))/(x^2-1^2)`

It is a law of exponents
`a^2-b^2=(a+b)(a-b)`

`((x+2)cancel((x+1)))/((x-1)cancel((x+1)))`

You are left with
`(x+2)/(x-1)`