Question

At what temperature (in K) would 4.0 moles of hydrogen gas in a 100 liter container exert a pressure of 1.00 atmospheres?

Answer 1

`color(red)(T=304.5K)`

Explanation:

Ideal Gas Law.
`(P*V)/(n*T)=R` or `PV=nRT`

P=1.00 atm
V=100 L
n=4.0 mol H
`color(red)(T=?)`
R=0.0821 `(atm*L)/(mol*K)`

`color(red)(T=(P*V)/(n*R)`
The Ideal Gas Law

`T=(1.00cancel(atm)*100cancel(L))/(4.0cancel(mol)*0.0821(cancel(atm*L)/(cancel(mol)*K))`
`color(red)(T=?)`