Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations? 9x-4y+z=-4 -x+2y-3z=20 4x+4y-z=43

1 Answer
May 15, 2018

x = 3, y=7, and z = -3

Explanation:

The augmented matrix is:

[ (9,-4,1,|,-4), (-1,2,-3,|,20), (4,4,-1,|,43) ]

Multiply row 1 by 8 and add it to row 1:

[ (1,12,-23,|,156), (-1,2,-3,|,20), (4,4,-1,|,43) ]

Add row 1 to row 2:

[ (1,12,-23,|,156), (0,14,-26,|,176), (4,4,-1,|,43) ]

Multiply row 1 by -4 and add it to row 3:

[ (1,12,-23,|,156), (0,14,-26,|,176), (0,-44,91,|,-581) ]

Multiply row 2 by 7/2 and add it to row 3:

[ (1,12,-23,|,156), (0,14,-26,|,176), (0,5,0,|,35) ]

Swap row 2 and row 3:

[ (1,12,-23,|,156), (0,5,0,|,35), (0,14,-26,|,176) ]

Divide row 2 by 5:

[ (1,12,-23,|,156), (0,1,0,|,7), (0,14,-26,|,176) ]

Multiply row 2 by -14 and add to row 3:

[ (1,12,-23,|,156), (0,1,0,|,7), (0,0,-26,|,78) ]

Divide row 2 by -26:

[ (1,12,-23,|,156), (0,1,0,|,7), (0,0,1,|,-3) ]

Multiply row 3 by 23 and add to row 1:

[ (1,12,0,|,87), (0,1,0,|,7), (0,0,1,|,-3) ]

Multiply row 2 by -12 and add to row 1:

[ (1,0,0,|,3), (0,1,0,|,7), (0,0,1,|,-3) ]