How do you multiply #4r^3(2r^2-7r)#?

1 Answer
akm06
May 15, 2018

You distribute the 4#x^3# to the 2#r^2# and the 7r. Answer: 8#r^5#- 2#8r^4#.

Explanation:

More specifically, you multiply the 4 and the two together, for a total of 8, and then you add the powers of the two r terms. This would total 8#r^5# for the first term. Next, multiply the 4 and the 7 together, for 28, and then add the powers. This would total 7#r^4#. Put the two terms together and the answer is 8#r^5#- 2#8r^4#.

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