Question

If I have a 247 mL bag at a temperature of 20.9 degrees C, and I leave it in my car which has a temperature of 64.0 degrees C, what will the new volume of the bag be?

Answer 1

`color(red)(0.283L)`

Explanation:

Charle's Law `(V1)/(T1)=(V2)/(T2)`
`V`'s unit must be in liters (L) and Kelvin (K)=`C^@+273.15` for `T`

First, convert `mL->L`
`247cancel(mL)*(1L)/(1000cancel(mL))=0.247L`
Second, convert the temperature `C^@->K`
`20.9^@C+273.15=294.05`
`64.0^@C+273.15=337.15K`

`V_1=color(red)(0.247L)`
`T_1=color(red)(294.05K)`
`V_2=color(red)(?)`
`T_2=color(red)(337.15K)`

Now, rearrange the formula to get `V_2`
`V_2=V_1*(T_2)/(T_1)`
`V_2=color(red)(0.247L)*color(red)(337.15cancel(K))/(color(red)(294.05cancel(K))`
`V_2=color(red)(?)`