How do you solve the following system: # -8x+2y=4 , 2x+5y=-1 #?

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Answer 1 · 2018-05-16T19:15:37

#x=-1/2,y=0#

#:.-8x+2y=4-------(1)#

#:.2x+5y=-1--------(2)#

#:.(2)xx4#

#:.8x+20y=-4-------(3)#

#:.(1)+(3)#

#:.22y=0#

#:.y=0#

substitute #y=0 in (2)#

#:.2x+5(0=-1)#

#:.2x=-1#

#:.x=-1/2#

~~~~~~~~~

check:-

substitute #x=-1/2# and # y=0# in #(1)#

#:.-8(-1/2)+2(0=4)#

#:.4+0=4#

#:.4=4#