How do you solve \frac { - 2} { 2t + 1} = - t22t+1=t?

1 Answer
May 16, 2018

-2/(2t+1)=(-t)22t+1=(t)
Multiply the whole equation by -(2t+1)(2t+1) to get rid of the minus sign
rArr2=t(2t+1)2=t(2t+1)
rArr2t^2+t-2=02t2+t2=0
Now just fill the quadratic formula
t_(1,2)=(-1+-sqrt(1^2-4(2(-2))))/(2*2)t1,2=1±124(2(2))22
t_(1,2)=(-1+-sqrt(1+16))/4t1,2=1±1+164
t_1=(-1+sqrt17)/4t1=1+174
t_2=(-1-sqrt17)/4t2=1174