Solve for x: log (5x-5)= 2 ?

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Answer 1 · 2018-05-18T03:16:10

#x=21#

.

#log(5x-5)=2#

We rewrite this equation in exponential form according to:

#log_ba=c# can be written as #a=b^c#

#5x-5=10^2#

#5x-5=100#

#5x=105#

#x=105/5=21#