Solve the system algebraically?

Question

$2 x + y = - 8$ $2x+y=-8$
$- x + y = 4$ $-x+y=4$

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Answer 1 · 2018-05-18T09:03:52

$(- 4, 0)$ $(-4,0)$

Take the second equation away from the first equation:
$2 x - (- x) + y - y = - 8 - 4$ $2x-(-x)+y-y=-8-4$

$3 x = - 12$ $3x=-12$

$x = - 4$ $x=-4$

Putting $x = - 4$ $x=-4$ into the original equation gives us:

$y = 4 - 4 = 0$ $y=4-4=0$

$(- 4, 0)$ $(-4,0)$