How do you evaluate #2^10# please solve and give an example and explanation? I really need help please.
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"A 5.00 L sample of helium at STP expands to 15.0 L. What is the new pressure on the gas?"
#2^10=2·2·2·2·2·2·2·2·2·2=1024#
The expresion #2^10# means that you have to repeat 2 as factor 10 times.
As you did long time ago, when you repeat a number adding a number of times you said for example #3+3+3+3=4·3=12#
Now the number you are repeating is as factor and the notation is #a^n=a·a·a·a····a# (n times)
Hope this helps
The powers of #10# are well known ...start with #1# and keep multiplying by #10# (just add another #0# each time. You get
#1," "10," "100," "1000," "10,000," "100,000 ....#
For the powers of #2#, start with #1# and keep multiplying by #2# which is the same as doubling each time. You get:
#1," "2," "4," "8," "16," "32," "64 .....#
#2xx2xx2xx2xx2xx2xx2xx2xx2xx2 =1024#
When you have multiplied by #2# a total of #10# times you have #2^10#
#
The answer will be #1024#
#2^10=2^4*2^4*2^2#
#:."when multiplying add the exponents together"#
#:.2^10=16*16*4=1024#
example:-
#:.3^16=3^4*3^4*3^4*3^2*3^2#
#:.3^16=81*81*81*9*9=43046721#
For #2^10:-#
"on your calculator(hp9s):- #press #2 "then press #x^y# then press #10# then press enter display#=1024#
