How do you solve #\frac { 3} { y + 2} = \frac { 1} { y - 2}#?

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Answer 1 · 2018-05-23T06:59:15

The solution is y=4

#3/(y+2)=1/(y-2)#

#=>3(y-2)=1(y+2)# [By cross multiplication]

#=> 3y-6=y+2#

#=> 3y-y=6+2#

#=>2y=8#

#=>y=8/2#

#=>y=4#

The solution is y= 4