How do you factor the expression $x^{3} y^{3} - 125$ $x^3y^3-125$ ?

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Answer 1 · 2018-05-24T18:59:34

$(x y - 5) ({(x y)}^{2} - 5 x y + 25)$ $(xy-5)((xy)^2-5xy+25)$

Use the formula $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ $a^3-b^3=(a-b)(a^2+ab+b^2)$

Answer 2 · 2018-05-24T19:24:21

$(x y - 5) (x^{2} y^{2} + 5 x y + 25)$ $(xy-5)(x^2y^2+5xy+25)$

subtraction of cubes;-

$:.a^3-b^3=(a-b)(a^2+ab+b^2)$

$x^3y^3-125$

$:.=(xy-5)(x^2y^2+5xy+5^2)$

$:.=(xy-5)(x^2y^2+5xy+25)$

How do you factor the expression x^3y^3-125x3y3−125x^3y^3-125?