Again with this!! I need a sum of 2 numbers that equals 20 and they both have a difference of 48, can you please help me? Also, i can't seem to understand this so could you kinda help with that also?

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Answer 1 · 2018-05-25T02:02:13

The numbers are #34# and #-14#.

Assume the two numbers are #x# and #y#.

#x + y = 20#

Rearrange to get:

#x = 20 - y#

Then use the second equation:

#x - y = 48#

Rearrange to get:

#x = 48 + y#

Then sub them into each other to get the formula:

#20 - y = 48 + y#

Solve:

#2y = -28#

#y = -14#

Go back to your first rearranged equation and plug #y# in.

#x = 20 - (-14)#

#x = 34#

Therefore, #x# and #y# are #34# and #-14#, respectively.