Again with this!! I need a sum of 2 numbers that equals 20 and they both have a difference of 48, can you please help me? Also, i can't seem to understand this so could you kinda help with that also?

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Answer 1 · 2018-05-25T02:02:13

The numbers are $34$ $34$ and $- 14$ $-14$ .

Assume the two numbers are $x$ $x$ and $y$ $y$ .

$x + y = 20$ $x + y = 20$

Rearrange to get:

$x = 20 - y$ $x = 20 - y$

Then use the second equation:

$x - y = 48$ $x - y = 48$

Rearrange to get:

$x = 48 + y$ $x = 48 + y$

Then sub them into each other to get the formula:

$20 - y = 48 + y$ $20 - y = 48 + y$

Solve:

$2 y = - 28$ $2y = -28$

$y = - 14$ $y = -14$

Go back to your first rearranged equation and plug $y$ $y$ in.

$x = 20 - (- 14)$ $x = 20 - (-14)$

$x = 34$ $x = 34$

Therefore, $x$ $x$ and $y$ $y$ are $34$ $34$ and $- 14$ $-14$ , respectively.