What is the force, in terms of Coulomb's constant, between two electrical charges of 14 C and 29 C that are 4 m apart?

2 Answers
May 25, 2018

"25.375k N"

Explanation:

Force between two charge particles is given by

"F" = ("kq"_1"q"_2)/"d"^2

Where "k" is Coulomb’s constant.

"F" = "k × 14 C × 29 C"/("4 m")^2 = "25.375k N"

May 25, 2018

Removed because the answer is incorrect.