What is the force, in terms of Coulomb's constant, between two electrical charges of $14 C$ and $29 C$ that are $4 m$ apart?

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Answer 1 · 2018-05-25T14:16:48

$"25.375k N"$

Force between two charge particles is given by

$"F" = ("kq"_1"q"_2)/"d"^2$

Where $"k"$ is Coulomb’s constant.

$"F" = "k × 14 C × 29 C"/("4 m")^2 = "25.375k N"$

Answer 2 · 2018-05-25T14:28:11

Removed because the answer is incorrect.

What is the force, in terms of Coulomb's constant, between two electrical charges of 14 C14 C and 29 C29 C that are 4 m 4 m apart?