Please solve q107 ?

enter image source here

1 Answer
May 26, 2018

|AFD|=4 " units"^2

Explanation:

enter image source here
Let |ABC| denote area of ABC
Given BE=EC, and |ABC|=48
=> |ABE|=|AEC|=48/2=24
given AF=FE,
=> |BAF|=|BEF|=24/2=12
draw a line joining D andE, as shown in the figure.
let |AFD|=a, => |FED|=a
=> |DEC|=|AEC|-|AED|=24-2a
as |DBE|=|DEC|, => 12+a=24-2a, => a=4
Hence, |AFD|=a=4 " units"^2