The chess club members bought 6 tickets to a tournament for $15. How much would they have paid if all 9 members wanted to go?

1 Answer
May 26, 2018

For nine members, it would cost 22.50

Explanation:

So we would set it up as a proportion to solve for x like this:

"6 tickets"/"$15" = "9 tickets"/x

So "tickets" refer to people. So since they brought 6 tickets for 6 people for 15 dollars, we need to cross multiply to see what we would get for x.

15*9=135 then 135/6=22.25

So for 9 members (or tickets), it would cost 22.50