2(60-(250-z/3))=z-110 how to find z?

1 Answer
Xr.Shim
May 27, 2018

z = -810

Explanation:

2(60-(250-z/3))=z-110
2((60*3)/(1*3)-((250*3)/(1*3)-z/3))=z-110
2(180/3-((750)/(3)-z/3))=z-110
2(180/3-(750)/(3)+z/3)=z-110
180/3-(750)/(3)+z/3=(z-110)/2
(z-570)/3=(z-110)/2
2(z-570)=3(z-110)
2z-1140=3z-330
-1140+330=3z-2z
z=-810

Related questions
Impact of this question
1051 views around the world
You can reuse this answer
Creative Commons License