What is the volume occupied by a mole of an ideal gas, if the pressure is 626 mm Hg and the temperature is 25.0 degrees Celsius?

1 Answer
May 31, 2018

V = "29.7 L"V=29.7 L

Explanation:

We can use the Ideal Gas Law to calculate the volume:

color(blue)(bar(ul(|color(white)(a/a)pV = nRTcolor(white)(a/a)|)))" "

We can rearrange the Ideal Gas Law to get

V = (nRT)/p

In this problem,

n = "1 mol"
R = (25.0 + 273.15) K = 298.15 K"

p = 626 color(red)(cancel(color(black)("mmHg"))) × "1 atm"/(760color(red)(cancel(color(black)("mmHg")))) = "0.8237 atm"

V = (1 color(red)(cancel(color(black)("mol"))) × "0.082 06 L"·color(red)(cancel(color(black)("atm"·"K"^"-1"·"mol"^"-1"))) × 298.15 color(red)(cancel(color(black)("K"))))/(0.8237 color(red)(cancel(color(black)("atm")))) = "29.7 L"