Help in Sequence and Series question!?

When a council offers free reflective house numbers, 30% of residents install them in the first month, the numbers in the second month are only 30% of those in the first month, and so on. What proportion of residents eventually installs them?

1 Answer
Jun 1, 2018

42.8% of the residents.

Explanation:

This is a Geometric Progression that starts at n = 1 (instead of 0).

Let R_0 = the initial number of residents.

Convert the percentage of residents that install the letters from 30% to a decimal:

d = 0.3

The number of residents that do the installation for any given month is:

R_n = R_0d^n, {n in ZZ, n >=1}

Let S = the infinite sum

S = R_0d+R_0d^2+R_0d^3+...

From the reference, we know that:

S = R_0+ R_0d+R_0d^2+R_0d^3+... = R_0/(1-d)

To obtain the formula that does not start with R_0, we subtract R_0 from the original formula:

S = R_0d+R_0d^2+R_0d^3+... = R_0/(1-d) - R_0

Substitute 0.3 for d:

S = R_0/(1-0.3) - R_0

Factor out R_0:

S = R_0(1/(1-0.3) - 1)

Use a calculator:

S = R_0(0.bar(428571)...)

This is approximately 42.8% of the residents.