How do you multiply $(x - 0.6) (x + 0.6)$ $(x - 0.6) ( x + 0.6)$ ?

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Answer 1 · 2018-06-03T01:44:53

$x^{2} - 0.36$ $x^2-0.36$

Given: $(x - 0.6) (x + 0.6)$ $(x-0.6)(x+0.6)$

Use the fact that $(a - b) (a + b) = a^{2} - b^{2}$ $(a-b)(a+b)=a^2-b^2$ .

Here, $a = x, b = 0.6$ $a=x,b=0.6$ .

$= x^{2} - {0.6}^{2}$ $=x^2-0.6^2$

$= x^{2} - 0.36$ $=x^2-0.36$

Answer 2 · 2018-06-03T01:49:25

$(x - 0.6) (x + 0.6) = x^{2} - 0.36$ $(x-0.6)(x+0.6) = x^2 - 0.36$

Use the Difference of Squares Identity $(a + b) (a - b) = a^{2} - b^{2}$ $(a+b)(a-b) = a^2 - b^2$

$(x - 0.6) (x + 0.6) = x^{2} - 0.36$ $(x-0.6)(x+0.6) = x^2 - 0.36$

How do you multiply (x - 0.6) ( x + 0.6)(x−0.6)(x+0.6)(x - 0.6) ( x + 0.6)?