What is #(6x^3-18x^2-12x)/(-6x)#?
2 Answers
Jun 3, 2018
Explanation:
#"each term on the numerator is divided by "-6x#
#=(6x^3)/(-6x)-(18x^2)/(-6x)-(12x)/(-6x)#
#=(cancel(6)x^((3-1)))/-cancel(6)-(cancel(18)^3x^((2-1)))/(-cancel(6)^1)-cancel(12x)^2/(-cancel(6x)^1)#
#=-x^2+3x+2#
Jun 3, 2018
Explanation: