What is the area of a circle with a circumference of 56.52 inches (in.)? Use 3.14 forimage.

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Answer 1 · 2018-06-05T17:11:18

$~~254 "in"^2$

$C_"circle" = 2pir$

$56.52= 2pir$

$28.26=pir$

$r=28.26/pi~~8.995$

$A_"circle" = pir^2$

$A_"circle" = pi(8.995)^2~~254.19$

We can combine the formulas:

$C = 2pir$

$C/(2pi) = r$

$A = pi(C/(2pi))^2$

$A = piC^2/(4pi^2)$

Now we have a formula for the area of a circle of any given circumference:

$A = C^2/(4pi)$

$C=56.52$

$A = 56.52^2/(4pi) ~~254.19$

Answer 2 · 2018-06-05T19:42:22

$254.34 "in"^2$

$:."circumference of a circle"=2pir$

$:.2pir=56.52"in"$

$:.r=56.52/(2pi)$

$:.r=56052/(2 xx3.14)$

$:.r=56.52/6.28$

$:.r=9$

$:."Area of a circle"= pi r^2$

$:.A=3.14 xx9^2$

$:.A=254.34"in"^2$