How will I solve this without substitution?

The integral is (1 + sin^2theta csctheta)d theta

2 Answers
Jun 5, 2018

Simplify using standard trig definitions

Explanation:

Recall the definition of csc as csctheta=1/sintheta. So this expression simplifies to be int1+sinthetad theta=theta-costheta+C

Jun 5, 2018

See explanation.

Explanation:

According to the definition of csc theta we have:

csc theta=1/sintheta

If we use this identity, then the integral is:

int (1+sin^2theta/sintheta)d theta= int(1+sintheta)d theta=theta -cos theta+C