Question

How do you write `(9x+6)(3x-2)` in standard quadratic form?

Answer 1

`27x^2-12`

Explanation:

Firstly, you need to know what standard quadratic form is. The standard quadratic form is `ax^2 + bx + c`.
Then, you expand the equation given to you:
`(9x+6)(3x-2)`
= `27x^2-18x+18x-12`
As you can see, your quadratic form has been satisfied.
Cancel out the `-18x+18x` since the sum would be zero.
Your answer would be:
`27x^2-12`