An object travels 16mtrs in 4sec and then another 16mtrs in 2 sec along a straight path. what are its average speed and average velocity?

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Answer 1 · 2018-06-08T00:26:06

Refer to the explanation.

The total distance traveled is:

$16 "m"+16 \ "m"=32 \ "m"$

The average speed is therefore:

$bars=d/t=(32 \ "m")/(6 \ "s")=5.bar(3) \ "m/s"$

Assuming that the direction did not change, the average velocity is:

$barv=(vecd)/t=(16 \ "m")/(6 \ "s")$

$~~5.33 \ "m/s towards the original direction"$

Answer 2 · 2018-06-08T01:00:30

The object travels $16" m"$ then it travels another $16" m"$ ; that is a total distance of $32" m"$

The first time that it moves takes $4" s"$ then the next time that it moves takes $2" s"$ ; that is a total time of $6" s"$

$"Average speed" = "Total distance"/"Total time"$

$"Average speed" = (32" m")/(6" s")$

$"Average speed" = 5.bar3" m/s"$

NOTE: The overbar indicates that the number repeats infinitely.

We can say nothing about the velocity because we are given no information that allows us to determine direction.