How do you write #y + 9= 4x - 8# in standard form?

2 Answers
Jun 11, 2018

#-4x+y=-17#

Explanation:

Standard for is given by

#Ax+By=C#

We essentially want our constants on the left, and the variables on the right. Let's subtract #4x# from both sides to get

#-4x+y+9=-8#

Next, let's subtract #9# from both sides to get

#-4x+y=-17#

We have our variables on one side, and the constants on the other, thus this equation is in standard form.

Hope this helps!

Jun 11, 2018

#-4x+y=-17#

Explanation:

Standard form uses the equation

#Ax+By=C#

So really all we have to do is get the #x# and #y# variable on one side of the equal sign and the regular number on the other side.

First, let’s get the variables together. Subtract #4x# from both sides:

#y+9-4x=-8#

Now, subtract #9# from both sides:

#y-4x=-8-9#

#y-4x=-17#

If you want to put it in traditional standard form like below you can, however it does not matter.

#-4x+y=-17#