How do you solve #-3+ 2n = 3n + 5#?

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Answer 1 · 2018-06-12T01:10:53

#n=-8#

We have to isolate the variable #n# on one side and the constants on the other. To start, subtract #2n# from both sides:

#-3=3n-2n+5#

#-3=n+5#

Now subtract #5# from both sides:

#-3-5=n#

#n=-8#

Hope this helps!