What is the simplified form of $(x-3)/(x^2+x-12) * (x+4)/(x^2 + 8x + 16)$ ?

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Answer 1 · 2018-06-12T03:53:46

$1/(x+4)^2$

First, factor the fractions:

$(x-3)/(x^2+x-12) * (x+4)/(x^2+8x+16)$

$(x-3)/((x-3)(x+4)) * (x+4)/((x+4)(x+4))$

Now, combine them:

$((x-3)(x+4))/((x-3)(x+4)^3)$

$(cancel((x-3))cancel((x+4)))/(cancel((x-3))(x+4)^(cancel3 color(white)"." color(red)2))$

$1/(x+4)^2$

Or if you want to expand it back out:

$1/(x^2+8x+16)$

Final Answer

What is the simplified form of (x-3)/(x^2+x-12) * (x+4)/(x^2 + 8x + 16)(x-3)/(x^2+x-12) * (x+4)/(x^2 + 8x + 16)?