What is the vertex form of #y=-x^2+4x+1#?
1 Answer
Jun 14, 2018
See explanation.
Explanation:
The vertex form of a quadratic function is:
#f(x)=a(x-p)^2+q#
where
#p=(-b)/(2a)#
and
#q=(-Delta)/(4a)#
where
#Delta=b^2-4ac#
In the given example we have:
So:
Finally the vertex form is: